document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37890>Question 37890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A runner decides to run out in the country. He begins to run at an average rate of 9 miles per hour. He runs a certain distance and then turns around and returns along the same route at an average rate of 6 minutes per hour. If the round trip took 2 and a half hours, how far did the runner travel before turning around? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23414 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/9+x/6=2.5 or (6x+9x)=2.5*54 or 15x=135 or x=135/15 or x=9 miles thus\r<BR>\n" );
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document.write( "9/9=1 hour & 9/6=1.5 hours thus 1+1.5=2.5 hours round trip. </SPAN>\n" );
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