document.write( "Question 326911: in a particular game, a fair die is tossed. if the number of spots showing is a six, you win $6, if the number of spots showing is a five, you win $3, and if the number of spots showing is 4, you win $1. if the number of spots showing is 1, 2, or 3 you win nothing. you are going to play the game twice.\r
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document.write( "The probability that you win over $10 in total on the two plays of the game is:\r
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document.write( "a- 1/6
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document.write( "b- 1/3
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document.write( "c- 1/36
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document.write( "d- 1/4\r
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document.write( "thanks \n" );
document.write( "
Algebra.Com's Answer #234120 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only way to get more than $10 in two plays is to roll a 6 twice. Rolling one die twice or two dice at the same time is identical from a probability standpoint. Probability of Boxcars is 1 in 36.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |