document.write( "Question 326888: Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? Can you sow all of your work so I can understand it more? Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #234110 by jessica43(140) ![]() You can put this solution on YOUR website! To solve this problem, you are going to have to first write two equations using what you know. \n" ); document.write( "First, you know that Tony and Belinda have a combined age of 56. This can be written as: \n" ); document.write( "T + B = 56 (where T = Tony's age, B = Belinda's age) \n" ); document.write( "Second, you know that Belinda is 8 more than twice Tony's age. This can be written as: \n" ); document.write( "B = 8 + 2T \n" ); document.write( "Now you can plug in the second equation into the first equation for B and solve for T: \n" ); document.write( "T + B = 56 \n" ); document.write( "T + (8 + 2T) = 56 \n" ); document.write( "8 + 3T = 56 \n" ); document.write( "3T = 48 \n" ); document.write( "T = 16 \n" ); document.write( "So Tony is 16 years old. \n" ); document.write( "Now plug this into the first equation to find B: \n" ); document.write( "T + B = 56 \n" ); document.write( "16 + B = 56 \n" ); document.write( "B = 40 \n" ); document.write( "So Belinda is 40 years old. \r \n" ); document.write( "\n" ); document.write( "Hope that helps! \n" ); document.write( " |