document.write( "Question 326889: find the coordinates of the vertex for the parabola f(x) =4xsquared-x+2 \n" ); document.write( "
Algebra.Com's Answer #234099 by Fombitz(32388)\"\" \"About 
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Convert to vertex form by completing the square,
\n" ); document.write( "\"f%28x%29=4x%5E2-x%2B2\"
\n" ); document.write( "\"f%28x%29=4%28x%5E2-%281%2F4%29x%29%2B2\"
\n" ); document.write( "\"f%28x%29=4%28x%5E2-%281%2F4%29x%2B1%2F64%29%2B2-4%2F64\"
\n" ); document.write( "\"f%28x%29=4%28x-1%2F8%29%5E2%2B128%2F64-4%2F64\"
\n" ); document.write( "\"f%28x%29=4%28x-1%2F8%29%5E2%2B31%2F16\"
\n" ); document.write( "The vertex is (1/8,31,16).
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