document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326840>Question 326840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the measure of one exterior angle of a regular polygon is 30 degrees how many sides does the polygon have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234082 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the measure of each exterior angle of a regular polygon, you just divide 360 degrees by the number of sides.  This can be written as:<BR>\n" );
document.write( "A = 360/s  (where A = measure of exterior angle, s = number of sides)<BR>\n" );
document.write( "Since we know that the measure of the angle is 30 degrees, we can plug this in for A and solve for s:<BR>\n" );
document.write( "A = 360/s<BR>\n" );
document.write( "30 = 360/s<BR>\n" );
document.write( "30s = 360<BR>\n" );
document.write( "s = 12<BR>\n" );
document.write( "So the polygon has 12 sides. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );