document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326831>Question 326831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6-3x=5x-10x+10 I came up with 1 as the answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234070 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer is actually 2.  To solve this, you need to combine like terms and then solve for x:<BR>\n" );
document.write( "6 - 3x = 5x - 10x + 10   (now combine 5x and -10x)<BR>\n" );
document.write( "6 - 3x = -5x + 10   (now add 5x to each side)<BR>\n" );
document.write( "6 + 2x = 10    (now subtract 10 from each side)<BR>\n" );
document.write( "2x - 4 = 0<BR>\n" );
document.write( "2x = 4<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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