document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37878>Question 37878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right triangle, if the legs are x feet and 3x+3 feet, and the hypotenuse is 25 feet, then solve for x by using the quadratic formula. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23406 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Pythagorean Theorem is<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "If we substitute in we have<BR>\n" );
document.write( "x^2 + (3x + 3)^2 = 25^2 and<BR>\n" );
document.write( "x^2 + 9x^2 + 18x + 9 = 625<BR>\n" );
document.write( "10x^2 + 18x - 616 = 0<BR>\n" );
document.write( "5x^2 + 9x - 308 = 0<BR>\n" );
document.write( "(5x + 44)(x - 7) = 0<BR>\n" );
document.write( "x = -44/5 or x = 7<BR>\n" );
document.write( "Since distance can't be negative,<BR>\n" );
document.write( "x = 7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );