document.write( "Question 326846: 18. Keiko bicycles 4 km/h faster than Dennis. In the same time it takes Dennis to bicycle 27 km, Deiko can bicycle 39 Km. How fast does each bicyclist travel? Dennis travels ?km/h
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document.write( "Keiko travels ? Km/h
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Algebra.Com's Answer #234052 by galactus(183)![]() ![]() You can put this solution on YOUR website! Remember that d=rt.\r \n" ); document.write( "\n" ); document.write( "In this case, we want time so we use t=d/r\r \n" ); document.write( "\n" ); document.write( "We are told that there times are equal. One is just traveling faster than the other.\r \n" ); document.write( "\n" ); document.write( "Dennis's time is 27/r\r \n" ); document.write( "\n" ); document.write( "Deiko's time is 39/(r+4)\r \n" ); document.write( "\n" ); document.write( "Since they are equal, we have \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, Dennis is going 9 kph and Deiko is traveling 13 kph.\r \n" ); document.write( "\n" ); document.write( "These types of problems are variations on a theme. Use d=rt and manipulate it accordingly. Since they said their times were equal, we use t=d/r. The distance is given, so all we have to do is solve for the rates by equating the time, t=d/r. \r \n" ); document.write( "\n" ); document.write( "See?. \n" ); document.write( " \n" ); document.write( " |