document.write( "Question 326846: 18. Keiko bicycles 4 km/h faster than Dennis. In the same time it takes Dennis to bicycle 27 km, Deiko can bicycle 39 Km. How fast does each bicyclist travel? Dennis travels ?km/h
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Algebra.Com's Answer #234052 by galactus(183)\"\" \"About 
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Remember that d=rt.\r
\n" ); document.write( "\n" ); document.write( "In this case, we want time so we use t=d/r\r
\n" ); document.write( "\n" ); document.write( "We are told that there times are equal. One is just traveling faster than the other.\r
\n" ); document.write( "\n" ); document.write( "Dennis's time is 27/r\r
\n" ); document.write( "\n" ); document.write( "Deiko's time is 39/(r+4)\r
\n" ); document.write( "\n" ); document.write( "Since they are equal, we have \"27%2Fr=39%2F%28r%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"27%28r%2B4%29=39r\"\r
\n" ); document.write( "\n" ); document.write( "\"27r%2B108=39r\"\r
\n" ); document.write( "\n" ); document.write( "\"108=12r\"\r
\n" ); document.write( "\n" ); document.write( "\"r=9\"\r
\n" ); document.write( "\n" ); document.write( "So, Dennis is going 9 kph and Deiko is traveling 13 kph.\r
\n" ); document.write( "\n" ); document.write( "These types of problems are variations on a theme. Use d=rt and manipulate it accordingly. Since they said their times were equal, we use t=d/r. The distance is given, so all we have to do is solve for the rates by equating the time, t=d/r. \r
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