document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37877>Question 37877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x: (2/5x)-(4/3x)=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23402 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The fractional equation<BR>\n" );
document.write( "(2/5x) - (4/3x) = 3<BR>\n" );
document.write( "can be simplified by multiplying all terms by the lowest common denominator, which is 15x in this case..thus we get<BR>\n" );
document.write( "15x[(2/5x) - (4/3x) = 3]<BR>\n" );
document.write( "6 - 20 = 45x<BR>\n" );
document.write( "-14 = 45x<BR>\n" );
document.write( "x = -14/45 </SPAN>\n" );
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