document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37749>Question 37749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is one-fourth the length. The perimeter of the rectangle is one hundred thirty feet. What is the width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23401 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have W = (1/4)L<BR>\n" );
document.write( "The area A = LW = 130.<BR>\n" );
document.write( "Substituting we have<BR>\n" );
document.write( "L((1/4)L) = 130<BR>\n" );
document.write( "(1/4)L^2 = 130<BR>\n" );
document.write( "L^2 = 520<BR>\n" );
document.write( "and <BR>\n" );
document.write( "L = sqrt(520) = 2(sqrt(130))<BR>\n" );
document.write( "Since W = (1/4)L, we have<BR>\n" );
document.write( "W = L/4 = (1/2)sqrt(130) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );