document.write( "Question 591: Will you please help me with the following problem?\r
\n" ); document.write( "\n" ); document.write( "Put the following quadratic in standard form, identify the vertex, y-intercept, and graph including two symmetrical points to the left and right of the vertex.
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Algebra.Com's Answer #234 by janinecb(25)\"\" \"About 
You can put this solution on YOUR website!
Different books actually have slightly different standard forms for the parabola. One version is:
\n" ); document.write( "\"y+=+a%28x+-+h%29%5E2+%2B+k\" Where (h, k) is the vertex.
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\n" ); document.write( "To find the y-intercept, just plug in zero for the x and solve for y.
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\n" ); document.write( "To find two symmetrical points, find two numbers the same distance to the left and right of the x value of the vertex. Then plug them in for x and solve for y.
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\n" ); document.write( "Example:
\n" ); document.write( "\"y+=+%28x+-+2%29%5E2+%2B+1\" The vertex is (2, 1).
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\n" ); document.write( "Plug in zero for x to find the y-intercept.
\n" ); document.write( "\"y+=+%280+-+2%29%5E2+%2B+1\"
\n" ); document.write( "\"y+=+%28-2%29%5E2+%2B+1\"
\n" ); document.write( "y = 4 + 1
\n" ); document.write( "y = 5 So the y-intercept in point form is (0, 5).
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\n" ); document.write( "Pick two x values that are the same distance from the x value of the vertex, such as 1 and 3. Then plug them into the equation to find the y values to go with them on the graph.
\n" ); document.write( "\"y+=+%281+-+2%29%5E2+%2B+1\"
\n" ); document.write( "\"y+=+%28-1%29%5E2+%2B+1\"
\n" ); document.write( "y = 1 + 1
\n" ); document.write( "y = 2 So one point is (1, 2).
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\n" ); document.write( "\"y+=+%283+-+2%29%5E2+%2B+1\"
\n" ); document.write( "\"y+=+%281%29%5E2+%2B+1\"
\n" ); document.write( "y = 1 + 1
\n" ); document.write( "y = 2 So a symmetrical point is (3, 2).
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\n" ); document.write( "\"graph%28300%2C+200%2C+-2%2C+6%2C+-2%2C+10%2C+%28x+-+2%29%5E2+%2B1%29\"
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