document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326708>Question 326708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a triangle that is 8x8x6 How do I find the Height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233942 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8x8x6 tells you it is isosceles.\r<BR>\n" );
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document.write( "An isosceles triangle can be ‘sliced down the middle between the two equal sides to make two equal right angled triangles.\r<BR>\n" );
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document.write( "Let 6 be the base and 8 be the two equal sides pointing up. Here you would have two right angled triangles with a base 3 and a hypotenuse 8 so using Pythagoras you can work out the height is the square root of 64 minus 9 = 55^0.5.\r<BR>\n" );
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document.write( "Therefore the height is 55^0.5 and the area of the full triangle (not the half sized triangles which are right-angled)\r<BR>\n" );
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document.write( "= 0.5 times 6 times 55^0.5 = 3 times 55^0.5\r<BR>\n" );
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document.write( "From this you can work out the height if one of the equal sides (8cm) was the base instead of the different side (6cm).\r<BR>\n" );
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document.write( "Area = 3 times 55^0.5 = 0.5 times 8 times height = 4 times height\r<BR>\n" );
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document.write( "Therefore height when the base is 8 = 0.75 times 55^0.5\r<BR>\n" );
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document.write( "So the two possibilities are:\r<BR>\n" );
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document.write( "Base 6; height 55^0.5\r<BR>\n" );
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document.write( "Base 8; height 0.75 times 55^0.5\r<BR>\n" );
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document.write( "I hope this explains without diagrams. </SPAN>\n" );
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