document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37875>Question 37875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 feet less than twice the width. If the area is 77 sq feet, then solve a quadratic equation to find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23394 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the info in the problem,<BR>\n" );
document.write( "L = 2W - 3<BR>\n" );
document.write( "We know the formula for the area is<BR>\n" );
document.write( "A = LW and it equals 77, so now substitute in for L and solve:<BR>\n" );
document.write( "A = LW = 77<BR>\n" );
document.write( "(2W - 3)W = 77<BR>\n" );
document.write( "2W^2 - 3W - 77 = 0<BR>\n" );
document.write( "(2W + 11)(w - 7) = 0<BR>\n" );
document.write( "W = -11/2  or  W = 7<BR>\n" );
document.write( "Length can't be negative, so W = 7.<BR>\n" );
document.write( "L = 2W - 3 = 2(7) - 3 = 11 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );