document.write( "Question 326720: Hello, I found out that a fraction of : (7x+1)/(x+1)(x-2) simplifies as follows :
\n" ); document.write( "2/(x+1) + 5/(x-2)\r
\n" ); document.write( "\n" ); document.write( "Could you please guide me as to how I can simplify similar fractions? Is it based solely on experience or is there some kind of methodology? I would be really grateful if you'd help me on this!\r
\n" ); document.write( "\n" ); document.write( "Sincerely yours,
\n" ); document.write( "Kollias Panos
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Algebra.Com's Answer #233939 by J2R2R(94)\"\" \"About 
You can put this solution on YOUR website!
Using partial fractions we have
\n" ); document.write( "(7x + 1)/[(x + 1)(x - 2)] = A/(x + 1) + B/(x - 2)\r
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\n" ); document.write( "\n" ); document.write( "Multiply throughout by (x + 1)(x - 2) gives
\n" ); document.write( "7x + 1 = A(x - 2) + B(x + 1)\r
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\n" ); document.write( "\n" ); document.write( "By putting x=2 we can eliminate A and get
\n" ); document.write( "7(2) + 1 = A(2 - 2) + B(2 + 1)
\n" ); document.write( "15 = 3B
\n" ); document.write( "B = 5\r
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\n" ); document.write( "\n" ); document.write( "Similarly by putting x=-1 we can eliminate B and get
\n" ); document.write( "7(-1) + 1 = A(-1 - 2) + B(-1 + 1)
\n" ); document.write( "-6 = -3A
\n" ); document.write( "A = 2\r
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\n" ); document.write( "\n" ); document.write( "Therefore (7x + 1)/[(x + 1)(x - 2)] = 2/(x + 1) + 5/(x - 2)\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "(7x + 1)/[(x + 1)(x - 2)] = [2(x - 2) + 5/(x + 1)]/[(x + 1)(x - 2)]\r
\n" ); document.write( "\n" ); document.write( "(2x - 4 + 5x + 5)/[ (x + 1)(x - 2)] = (7x + 1)/[(x + 1)(x - 2)]\r
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\n" ); document.write( "\n" ); document.write( "So using this example should enable you to work out other fractions like this using this method.
\n" ); document.write( "It is a bit more difficult for repeated factors and factors of higher orders but for the moment we will stick to non-repeated linear factors.
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