document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326733>Question 326733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measures of two complementary angles such that the larger angle is six less than five times the smaller angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233937 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one angle be x<BR>\n" );
document.write( "the other angle is 5x-6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "The sum of these angles = 90 deg<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+5x-6=90<BR>\n" );
document.write( "6x-6=90<BR>\n" );
document.write( "add 6<BR>\n" );
document.write( "6x-6 + 6 = 90+6<BR>\n" );
document.write( "6x=96<BR>\n" );
document.write( "divide by 6<BR>\n" );
document.write( "6x/6=96/6<BR>\n" );
document.write( "x=16 one angle<BR>\n" );
document.write( "the other angle is 5x-6<BR>\n" );
document.write( "=5*16-6<BR>\n" );
document.write( "=80-6<BR>\n" );
document.write( "=74 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );