document.write( "Question 326734: Charlie has scores of 88, 95, and 89 on the first three tests. What score must he make on the fourth test so that the average of all four tests is exactly 93? \r
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document.write( "a.91.25 b.93 c.95 1/3 d.97 e.100\r
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Algebra.Com's Answer #233933 by AAfter Search(61)![]() ![]() ![]() You can put this solution on YOUR website! Let Charlie scores N in the fourth test to get an average of 93 marks. \n" ); document.write( "Hence, (88 + 95 + 89 + N)/4 = 93 \n" ); document.write( "=> 272 + N = 4 x 93 = 372 \n" ); document.write( "=> N = 372 - 272 = 100 \n" ); document.write( "Hence, Charlie must score 100 in the fourth test to get an average of 93 marks in all four tests. \n" ); document.write( " |