document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326722>Question 326722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much quantity of 15% of acid solution must be added to 8L of 30% solution of the same acid to obtain 25% solution for duty cleaning? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233930 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  15% of acid solution ---let it be x liters<BR>\n" );
document.write( "30% solution --------8 liters<BR>\n" );
document.write( "mixture  25% solution (8+x) liters<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.15x+0.08*30=0.25(8+x)<BR>\n" );
document.write( "0.15x+2.4 =2+0.25x<BR>\n" );
document.write( "add -2.4<BR>\n" );
document.write( "0.15x+2.4-2.4 = 2-2.4 +0.25x<BR>\n" );
document.write( "0.15x = 0.4+0.25x<BR>\n" );
document.write( "0.1x= 0.4<BR>\n" );
document.write( "x= 4 liters of  15% solution </SPAN>\n" );
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