document.write( "Question 326710: A woman has invested money in two accounts. Part of the money is invested in an account paying 7%
\n" ); document.write( "interest, and twice that amount is invested in an account paying 9% interest. After one year, the total
\n" ); document.write( "interest on the two investments is $500. How much did the woman invest at each rate?
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Algebra.Com's Answer #233926 by mananth(16946)\"\" \"About 
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account paying 7% let the amount invested be x
\n" ); document.write( "twice that amount account paying 9% = 2x
\n" ); document.write( "interest after one year,= $500.
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\n" ); document.write( "0.07x +0.09*2x=500
\n" ); document.write( "0.07x+0.18x=500
\n" ); document.write( "0.25x=500
\n" ); document.write( "divide by 0.25
\n" ); document.write( "0.25x/0.25 = 500/0.25
\n" ); document.write( "x= 500/0.25
\n" ); document.write( "=$ 2000 at 7%
\n" ); document.write( "2x = 2*2000 = $4000 at9%
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