document.write( "Question 326710: A woman has invested money in two accounts. Part of the money is invested in an account paying 7%
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document.write( "interest, and twice that amount is invested in an account paying 9% interest. After one year, the total
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document.write( "interest on the two investments is $500. How much did the woman invest at each rate? \n" );
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Algebra.Com's Answer #233926 by mananth(16946)![]() ![]() You can put this solution on YOUR website! account paying 7% let the amount invested be x \n" ); document.write( "twice that amount account paying 9% = 2x \n" ); document.write( "interest after one year,= $500. \n" ); document.write( ".. \n" ); document.write( "0.07x +0.09*2x=500 \n" ); document.write( "0.07x+0.18x=500 \n" ); document.write( "0.25x=500 \n" ); document.write( "divide by 0.25 \n" ); document.write( "0.25x/0.25 = 500/0.25 \n" ); document.write( "x= 500/0.25 \n" ); document.write( "=$ 2000 at 7% \n" ); document.write( "2x = 2*2000 = $4000 at9% \n" ); document.write( " |