document.write( "Question 326693: There are 3 fewer dimes than nickels. The collection totals $1.35. How many dimes are in the collection? \n" ); document.write( "

Algebra.Com's Answer #233905 by mananth(16946) $\"\"$ $\"About$

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let nickels be x
\n" ); document.write( "dimes = x-3
\n" ); document.write( "..
\n" ); document.write( "value of coins = 135 cents
\n" ); document.write( "..
\n" ); document.write( "5x+10(x-3)=135
\n" ); document.write( "5x+10x-30=135
\n" ); document.write( "15x-30=135
\n" ); document.write( "add 30
\n" ); document.write( "15x-30+30=135+30
\n" ); document.write( "15x=165
\n" ); document.write( "divide by 15
\n" ); document.write( "15x/15=165/15
\n" ); document.write( "x=11 nickels
\n" ); document.write( "dimes will be x-3= 11-3=8
\n" ); document.write( "..
\n" ); document.write( "CHECK
\n" ); document.write( "11*5+10*8=135 \n" ); document.write( "

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