document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37792>Question 37792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank contains gallons of water. Each day one-third of the water in the tank is removed and not replaced. How much water remains in the tank at the end of 6 days?\r<BR>\n" );
document.write( "\n" );
document.write( "i tried doing this a few times and im not getting the right answer. I think you write it like this: a=5832(1/3)^(6-1) right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23389 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you're close.\r<BR>\n" );
document.write( "\n" );
document.write( "If 1/3 is removed, 2/3 is what's left.<BR>\n" );
document.write( "Therefore, if 5832 gallons were originally there,<BR>\n" );
document.write( "x0 = 5832<BR>\n" );
document.write( "x1 = 5832(2/3) (after 1 day)<BR>\n" );
document.write( "x2 = 5832(2/3)(2/3)  (after 2 days)<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".<BR>\n" );
document.write( "x6 = 5832(2/3)^6 (after 6 days) =<BR>\n" );
document.write( "512 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );