document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37821>Question 37821</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0199142785/algebrahomeworkh>General  Mathematics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 66. The second number is twice the first and six less than the third. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23388 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Make the numbers a, b, c.<BR>\n" );
document.write( "We are given a+b+c=66, b=2a, and b=c-6.<BR>\n" );
document.write( "We can solve for a and c in terms of b, so a=b/2, c=b+6.<BR>\n" );
document.write( "Now, substitute a and c into the first equation, so b/2 + b + b+6 = 66, so (5/2)b=60, and b=24.  Now solving for a and c gives a=b/2=12 and c=b+6=30. </SPAN>\n" );
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