document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37777>Question 37777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x: (2/5x)-(4/3x)=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23383 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for subtraction, we need a common denominator.  In this case, the least common denominator is 15x, so we multiply 2/5x by 3/3, and multiply 4/3x by 5/5.<BR>\n" );
document.write( "So we have (6/15x)-(20/15x)=3.  Now we subtract and get (6-20)/15x=3.  We multiply both sides by 15x, and get 6-20=45x, so -14=45x.  Dividing both sides by 45 gives -14/45=x.<BR>\n" );
document.write( "You can substitute this x into the original equation to check you are right. </SPAN>\n" );
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