document.write( "Question 326598: The areao of a picture projected on a wall varies directly as the sqaure of the disance from the projector to the wall.If a 10ft distance produces a 16ft squared picture, what is the area of a picture produced when the projection unit is moved to a distance 20ft from the wall? \n" ); document.write( "
Algebra.Com's Answer #233829 by alanc(27)\"\" \"About 
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We are given the relation: Area of pic = constant * d^2, where d is distance from projector to wall.\r
\n" ); document.write( "\n" ); document.write( "For d = 10, we have A = 16 ft sqrd
\n" ); document.write( "Now given d = 20 what is A?\r
\n" ); document.write( "\n" ); document.write( "constant = 16/10*10\r
\n" ); document.write( "\n" ); document.write( "new A = [16/100] * 20*20 = 16 * 4 = 64 ft sqrd.\r
\n" ); document.write( "\n" ); document.write( "Answer the new picture is 64 ft squared.
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