document.write( "Question 326585: Can anyone help me solve this problem, its says find the solution set for
\n" ); document.write( "x2-3x-10 less than or equal to 0
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Algebra.Com's Answer #233828 by alanc(27)\"\" \"About 
You can put this solution on YOUR website!
The solution set is a set of x-values that satisfy x^2 - 3x - 10 <= 0. It will be an interval.\r
\n" ); document.write( "\n" ); document.write( "Factor x^2 - 3x - 10 into (x - 5)*(x + 2), because 2 * (-5) = -10 and 2 - 5 = -3.\r
\n" ); document.write( "\n" ); document.write( "First find x values such that (x - 5)*(x + 2) <= 0.\r
\n" ); document.write( "\n" ); document.write( "for (x - 5) we see for x <= 5 (x - 5) <= 0
\n" ); document.write( "for (x - 5) we see for x > 5 (x - 5) > 0\r
\n" ); document.write( "\n" ); document.write( "for (x + 2) we see for x <= -2 (x + 2) <= 0
\n" ); document.write( "for (x + 2) we see for x > -2 (x + 2) > 0\r
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\n" ); document.write( "\n" ); document.write( "draw a line -----------------0++++++++++++++++++++
\n" ); document.write( " 5
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\n" ); document.write( "\n" ); document.write( "(x-5)*(x+2) : ++++++++0--------0++++++++++++++++++++\r
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\n" ); document.write( "\n" ); document.write( "so (x-5)*(x+2) <= 0 when -2 <= x <= 5\r
\n" ); document.write( "\n" ); document.write( "Solution set : -2 <= x <=5\r
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