document.write( "Question 326467: Three forces with magnitudes of 250 ibs 60degrees N of E, 100 ibs 30degrees N of W, and 200 ibs S act on an object. Find the direction and magnitude of the resultant force. \r
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document.write( "I have no clue how to even begin a problem like this, thank you for taking the time to look at this. \n" );
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Algebra.Com's Answer #233731 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! First pick a coordinate system. \n" ); document.write( "Let North be positiive y. \n" ); document.write( "Let East be positive x. \n" ); document.write( "Then find the x,y components of each force. \n" ); document.write( "\"250 lbs 60 degrees N of E\"=250(cos(60),sin(60))=(125,216.5) \n" ); document.write( "\"100 lbs 30 degrees N of W\"=100(cos(150),sin(150))= (-86.6,50) \n" ); document.write( "\"200 lbs S\"=200(0,-1)=(0,-200) \n" ); document.write( "Then sum the x and y components to get the resultant. \n" ); document.write( "(Fx,Fy)=(125,216.5)+(-86.6,50)+(0,-200) \n" ); document.write( "(Fx,Fy)=(38.4,66.5) \n" ); document.write( "You can find the resultant magnitude and direction, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "76.8 lbs 60 degrees North of East. \n" ); document.write( " act on an object. Find the direction and magnitude of the resultant force. \n" ); document.write( " \n" ); document.write( " |