document.write( "Question 326467: Three forces with magnitudes of 250 ibs 60degrees N of E, 100 ibs 30degrees N of W, and 200 ibs S act on an object. Find the direction and magnitude of the resultant force. \r
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Algebra.Com's Answer #233731 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
First pick a coordinate system.
\n" ); document.write( "Let North be positiive y.
\n" ); document.write( "Let East be positive x.
\n" ); document.write( "Then find the x,y components of each force.
\n" ); document.write( "\"250 lbs 60 degrees N of E\"=250(cos(60),sin(60))=(125,216.5)
\n" ); document.write( "\"100 lbs 30 degrees N of W\"=100(cos(150),sin(150))= (-86.6,50)
\n" ); document.write( "\"200 lbs S\"=200(0,-1)=(0,-200)
\n" ); document.write( "Then sum the x and y components to get the resultant.
\n" ); document.write( "(Fx,Fy)=(125,216.5)+(-86.6,50)+(0,-200)
\n" ); document.write( "(Fx,Fy)=(38.4,66.5)
\n" ); document.write( "You can find the resultant magnitude and direction,
\n" ); document.write( "\"r=sqrt%2838.4%5E2%2B66.5%5E2%29=76.8\"
\n" ); document.write( "\"tan%28theta%29=66.5%2F38.4\"
\n" ); document.write( "\"theta=60\"
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\n" ); document.write( "76.8 lbs 60 degrees North of East.
\n" ); document.write( " act on an object. Find the direction and magnitude of the resultant force.
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