document.write( "Question 326419: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy 78% nickel? \n" ); document.write( "

Algebra.Com's Answer #233704 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let X be the number of mg of 45% nickel.
\n" ); document.write( " $\"45X%2B100%286%29=78%28X%2B6%29\"$
\n" ); document.write( " $\"45X%2B600=78X%2B468\"$
\n" ); document.write( " $\"-33X=-132\"$
\n" ); document.write( " $\"highlight%28X=4%29\"$
\n" ); document.write( ".
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\n" ); document.write( "4 mg of 45% nickel needs to be added.
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