document.write( "Question 326331: Hi i have 2 graphs y=8+2cos((pix)/6) and y= 3.5+e^(0.07x) and i need to find the values of x when y1=y2 aka 8+2cos((pix)/6)= 3.5+e^(0.07x but don't know how to do it any help would be great. \n" ); document.write( "
Algebra.Com's Answer #233698 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "Three solutions from www.wolframalpha.com, just type in the equation
\n" ); document.write( "8+2cos((pi*x)/6)=(3.5+e^(0.07x))
\n" ); document.write( "\"x1=16.40988\"
\n" ); document.write( "\"x2=20.79707\"
\n" ); document.write( "\"x3=25.46053\"
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\n" ); document.write( "http://www.wolframalpha.com/input/?i=8%2B2cos%28%28pi*x%29%2F6%29%3D%283.5%2Be%5E%280.07x%29%29
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