document.write( "Question 326332: In using the factoring method of solving quadratic equations, we put it in the form: \r
\n" ); document.write( "\n" ); document.write( "(x+a)(x+b) = 0. Where a and b are two constants (think of them as two “numbers”).\r
\n" ); document.write( "\n" ); document.write( "If the right-hand side of this equation is not zero (let’s say another constant \"c\"), do you think it can be solved? If so, how? If not, why not?
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Algebra.Com's Answer #233678 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let's presume you are faced with the equation:\r
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\n" ); document.write( "\n" ); document.write( "Where , , and are constants.\r
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\n" ); document.write( "\n" ); document.write( "Step one is to apply FOIL to the two binomials in the LHS.\r
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\n" ); document.write( "\n" ); document.write( "Then add to both sides.\r
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\n" ); document.write( "\n" ); document.write( "Then combine the constants so that and to write:\r
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\n" ); document.write( "\n" ); document.write( "Then, if you can find numbers and such that and , then you can factor your equation:\r
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\n" ); document.write( "\n" ); document.write( "which has roots and \r
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\n" ); document.write( "\n" ); document.write( "barring that you can use the quadratic formula to write:\r
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\n" ); document.write( "\n" ); document.write( "to find your two roots.\r
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