document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37863>Question 37863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simlify. (x-y/x+y)+(x+y/x-y)<BR>\n" );
document.write( "x2-y+xy/x+x3-xy2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23367 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can use the criss-cross method for this one...<BR>\n" );
document.write( "(x-y/x+y)+(x+y/x-y) =<BR>\n" );
document.write( "[(x - y)^2 + (x + y)^2] / (x^2 - y^2) =<BR>\n" );
document.write( "[x^2 - 2xy + y^2 + x^2 + 2xy + y^2) / (x^2 - y^2) =<BR>\n" );
document.write( "2(x^2 + y^2) / (x^2 - y^2)<BR>\n" );
document.write( "The criss-cross method is<BR>\n" );
document.write( "A/B ± C/D = (AD ± BD) / BD </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );