document.write( "Question 326330: A garden is 78sq yd and the length is 5 less than 3times the width. What is the dimensions? \n" ); document.write( "
Algebra.Com's Answer #233612 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = 3x-5
\n" ); document.write( "Area = 78 sq. yards
\n" ); document.write( "\"x%283x-5%29=78\"
\n" ); document.write( "\"3x%5E2-5x=78\"
\n" ); document.write( "add -78 to both sides
\n" ); document.write( "\"3x%5E2-5x-78+=78-78\"
\n" ); document.write( "\"3x%5E2-5x-78=0\"\r
\n" ); document.write( "\n" ); document.write( "the roots of the equation x1, x2 can be found out by the formula
\n" ); document.write( "\"x1=%28-b+%2Bsqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "a= 3 , b= -5 , c = -78
\n" ); document.write( "\"x1=%28-%28-5%29+%2Bsqrt%28%28-5%29%5E2-4%2A3%2A-78%29%29%2F%282%2A3%29\"
\n" ); document.write( "x1=6 yards the width
\n" ); document.write( "length = 3x-5 = 3*6-5
\n" ); document.write( "=13 yards
\n" ); document.write( "x2= -4.3333
\n" ); document.write( "x2 is negative so we ignore
\n" ); document.write( "
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