document.write( "Question 326290: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft.\r
\n" ); document.write( "\n" ); document.write( "I know that A = W(L)
\n" ); document.write( "so I think it should look like 84=x(x+8).
\n" ); document.write( "I also know the dimensions are 6ft by 14ft. I just can't figure out how to solve the equation once it moves to 84= x^2(8x)
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Algebra.Com's Answer #233587 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "So far, so good. . Looks like it has the makings of a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "Let's see, -6 times 14 is -84 and -6 plus 14 is 8, so:\r
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\n" ); document.write( "\n" ); document.write( "So:\r
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\n" ); document.write( "\n" ); document.write( "Discard the negative root because you are looking for a positive measure of length.\r
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\n" ); document.write( "\n" ); document.write( "The width is 6, hence the length is 6 plus 8 = 14. \r
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