document.write( "Question 326290: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft.\r
\n" );
document.write( "\n" );
document.write( "I know that A = W(L)
\n" );
document.write( "so I think it should look like 84=x(x+8).
\n" );
document.write( "I also know the dimensions are 6ft by 14ft. I just can't figure out how to solve the equation once it moves to 84= x^2(8x) \n" );
document.write( "
Algebra.Com's Answer #233587 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So far, so good. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's see, -6 times 14 is -84 and -6 plus 14 is 8, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Discard the negative root because you are looking for a positive measure of length.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The width is 6, hence the length is 6 plus 8 = 14. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |