document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326222>Question 326222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> As of July 2003, the population of India was estimated to be 1,050,000,000, with an annual growth rate of 1.47%. If the growth rate remains the same, how large will the population be in 50 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233574 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the standard compound interest formula.\r<BR>\n" );
document.write( "\n" );
document.write( "A = P(1+r)^n<BR>\n" );
document.write( "where A is the population<BR>\n" );
document.write( "P is the principal or starting amount<BR>\n" );
document.write( "r is the annual rate of growth<BR>\n" );
document.write( "n is the number of years\r<BR>\n" );
document.write( "\n" );
document.write( "A = 1050000000(1+0.0147)^50<BR>\n" );
document.write( "A = 1050000000(1.0147)^50<BR>\n" );
document.write( "A = 1050000000(2.074354695396870268818935813…<BR>\n" );
document.write( "A = 2,178,072,430<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );