document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326253>Question 326253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $60 a pound that she  wishes to mix with 40 pounds of coffee worth $90 a pound to get a mixture that can be sold for $80 a pound. How many pounds of the $60 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233544 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $60 a pound <BR>\n" );
document.write( "mix with 40 pounds of coffee worth $90 <BR>\n" );
document.write( "can be sold for $80 a pound. <BR>\n" );
document.write( "..<BR>\n" );
document.write( "let $60 coffee be x pounds<BR>\n" );
document.write( "$90 coffee 40 pounds<BR>\n" );
document.write( "Total $ 80 , 40+x pounds<BR>\n" );
document.write( "..<BR>\n" );
document.write( "60x+90*40=80(40+x)<BR>\n" );
document.write( "60x +3600=80x+3200<BR>\n" );
document.write( "20x=400<BR>\n" );
document.write( "x= 20 pounds </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );