document.write( "Question 37856: Five men were to share the treasure with Long John Silver. If the treasure were split in the following ratio 2:5:7:10:20:50, and the least amount any of the six pirates recieved was 14,000 pounds of gold, what is the total weight of the treasure?\r
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Algebra.Com's Answer #23354 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
If the ratios are
\n" ); document.write( "2:5:7:10:20:50
\n" ); document.write( "and the smallest portion is 14,000 pounds, we can call the smallest portion 2x...
\n" ); document.write( "Thus the sum of the treasure is
\n" ); document.write( "2x + 5x + 7x + 10x + 20x + 50x = 94x
\n" ); document.write( "and since 2x = 14,000 we have
\n" ); document.write( "x = 7,000 so that
\n" ); document.write( "94x = 94(7,000) = 658,000 pounds of gold.
\n" ); document.write( "Arggghhhh!
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