document.write( "Question 326194: Sove using factoring and principle of zero products. Must show all work. (please explain how you did this so I can try to understand) Thank you in advance:
\n" ); document.write( "2x^2+x=42+9x
\n" ); document.write( "

Algebra.Com's Answer #233521 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
\"2x%5E2%2Bx\"\"%22%22=%22%22\"\"42%2B9x\"
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "The other tutor's solution is correct; however there is one step\r\n" );
document.write( "he did not do, which would have made the factoring easier.\r\n" );
document.write( "\r\n" );
document.write( "Get a zero on the right by adding \"red%28-42-9x%29\" to both sides\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2%2Bx\"\"red%28-42-9x%29\"\"%22%22=%22%22\"\"42%2B9x\"\"red%28-42-9x%29\"\r\n" );
document.write( "\r\n" );
document.write( "Combine like terms and simplify:\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2\"\"%22%22-%22%22\"\"8x\"\"%22%22-%22%22\"\"42\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Since all the numbers are even we can divide every term by \"red%282%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2%2Fred%282%29\"\"%22%22-%22%22\"\"8x%2Fred%282%29\"\"%22%22-%22%22\"\"42%2Fred%282%29\"\"%22%22=%22%22\"\"0%2Fred%282%29\"\r\n" );
document.write( "\r\n" );
document.write( "[That is the step which the other tutor did not do, which makes it easier\r\n" );
document.write( "to factor.]\r\n" );
document.write( "\r\n" );
document.write( "Simplify:\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2\"\"%22%22-%22%22\"\"4%2Ax\"\"%22%22-%22%22\"\"red%2821%29\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "We must factor that.\r\n" );
document.write( "\r\n" );
document.write( "I did some coloring so I can refer to the parts:\r\n" );
document.write( "\r\n" );
document.write( "List all the ways to factor the red number 21 using two factors,\r\n" );
document.write( "(list the larger factor first):\r\n" );
document.write( "\r\n" );
document.write( "\"21\"\"x\"\"1\"\r\n" );
document.write( " \"7\"\"x\"\"3\"\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2\"\"%22%22-%22%22\"\"4%2Ax\"\"red%28%22%22-%22%22%29\"\"21\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Notice that the red sign (the one just before the 21 is \"red%28%22%22-%22%22%29\"\r\n" );
document.write( "\r\n" );
document.write( "Put that sign between those numbers above instead of the multiplication \r\n" );
document.write( "sign, and give the answer:\r\n" );
document.write( "\r\n" );
document.write( "\"21\"\"%22%22-%22%22\"\"1\"\"%22%22=%22%22\"\"20\"\r\n" );
document.write( " \"7\"\"%22%22-%22%22\"\"3\"\"%22%22=%22%22\"\"red%284%29\"\r\n" );
document.write( "\r\n" );
document.write( "Notice that the \"red%284%29\" is the same as the middle coefficient\r\n" );
document.write( "ignoring the sign: \r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2\"\"%22%22-%22%22\"\"red%284%29x\"\"%22%22-%22%22\"\"21\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Therefore write this:\r\n" );
document.write( "\r\n" );
document.write( "\"%22%28x%22\"\"%22%22\"\"%22%22\"\"%227%29%22\"\"%22%28x%22\"\"%22%22\"\"%22%22\"\"%223%29%22\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Finally we put the signs in.  7 is the larger factor, and the red\r\n" );
document.write( "sign (the sign before the \"4%2Ax\" is \"red%28%22%22-%22%22%29\" in this:\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2\"\"red%28%22%22-%22%22%29\"\"4%2Ax\"\"%22%22-%22%22\"\"21\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "So we place that sign before the 7\r\n" );
document.write( "\r\n" );
document.write( "\"%22%28x%22\"\"red%28%22%22-%22%22%29\"\"%227%29%22\"\"%22%28x%22\"\"%22%22\"\"%22%22\"\"%223%29%22\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Next we place whichever sign before the 3 which will cause the product\r\n" );
document.write( "to come out to be \"-21\", the last term of \"x%5E2\"\"%22%22-%22%22\"\"4%2Ax\"\"%22%22-%22%22\"\"21\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "That sign would have to be \"%22%22%2B%22%22\", so we have\r\n" );
document.write( "now completely factored the left side:\r\n" );
document.write( "\r\n" );
document.write( "\"%22%28x%22\"\"red%28%22%22-%22%22%29\"\"%227%29%22\"\"%22%28x%22\"\"%22%2B%22\"\"%223%29%22\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Next we use the zero-factor principle.\r\n" );
document.write( "\r\n" );
document.write( "Each of the factors \"%22%28x%22\"\"%22%22-%22%22\"\"%227%29%22\" and \"%22%28x%22\"\"%22%22%2B%22%22%29\"\"%223%29%22\" represents some number.  \r\n" );
document.write( "Since their product must equal to 0,\r\n" );
document.write( "it is obvious that one of them is equal to 0.  But which one?\r\n" );
document.write( "We cannot tell, so it would be correct if \"%22%28x%22\"\"%22%22-%22%22\"\"%227%29%22\" were\r\n" );
document.write( "0 and \"%22%28x%22\"\"%22%22%2B%22%22\"\"%223%29%22\" something else. OR, it would also\r\n" );
document.write( "be correct if \"%22%28x%22\"\"%22%22%2B%22%22\"\"%223%29%22\" were 0 and \"%22%28x%22\"\"%22%22-%22%22\"\"%227%29%22\" were something else. \r\n" );
document.write( "\r\n" );
document.write( "That's why there are two solutions to a quadratic equation. So we\r\n" );
document.write( "have to consider both possibilities:\r\n" );
document.write( "\r\n" );
document.write( "\"x\"\"%22%22-%22%22\"\"7\"\"%22%22=%22%22\"\"0\" OR \"x\"\"%22%22%2B%22%22\"\"3\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Solvving those we have two possibilities for solutions:\r\n" );
document.write( "\r\n" );
document.write( "\"x\"\"%22%22=%22%22\"\"7\" OR \"x\"\"%22%22=%22%22\"\"-3\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );