document.write( "Question 326194: Sove using factoring and principle of zero products. Must show all work. (please explain how you did this so I can try to understand) Thank you in advance:
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document.write( "2x^2+x=42+9x \n" );
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Algebra.Com's Answer #233515 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! subtracting 42+9x ___ 2x^2 - 8x - 42 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the factors of 2x^2 are 2x and x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the factors of -42 are (±1, ±42), (±2, ±21), (±3, ±14), (±6, ±7)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you need to \"combine\" the 2x and x with one of the other pairs of factors to end up with -8x \n" ); document.write( "___ the \"combining\" is summing the products of the pairs by FOILing\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x times 3 is 6x ___ x times -14 is -14x ___ this gives you the -8x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so the factors are ___ (2x - 14) and (x + 3) ___ (2x - 14)(x + 3) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the zero principle means that any (or all) of the quantities, whose product is zero, must be zero\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 14 = 0 ___ 2x = 14 ___ x = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 3 = 0 ___ x = -3 \n" ); document.write( " |