document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326130>Question 326130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of the yard is  4 less than 3 times the width of the yard. if the perimeter is 180ft. find the dimensions of the yard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233478 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W-4<BR>\n" );
document.write( "P=2L=2W<BR>\n" );
document.write( "180=2(3W-4)+2W<BR>\n" );
document.write( "180=6W-8+2W<BR>\n" );
document.write( "180=8W-8<BR>\n" );
document.write( "8W=180+8<BR>\n" );
document.write( "8W=188<BR>\n" );
document.write( "W=188/8<BR>\n" );
document.write( "W=23.5 yds.<BR>\n" );
document.write( "L=3*23.5-4<BR>\n" );
document.write( "L=70.5-4<BR>\n" );
document.write( "L=66.5 ans.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "180=2*66.5+2*23.5<BR>\n" );
document.write( "180=133+47<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );