document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37828>Question 37828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> S(with a sideways 8 beside it)=8-2+1/2+...=?  Please help!  I am so horrible at this! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23346 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes, okay...this is an infinite sum with the first term equalling 8 and the common ratio being -1/4...<BR>\n" );
document.write( "The formula for this is<BR>\n" );
document.write( "a-sub-1 / (1 - r)<BR>\n" );
document.write( "So plugging in we get...<BR>\n" );
document.write( "8 / (1 - (-1/4)) =<BR>\n" );
document.write( "8 / (5/4) =<BR>\n" );
document.write( "32/5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );