document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37842>Question 37842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would please like your help with this problem: 5x-3(2x-1)=5-3(-x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23339 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "5x - 3(2x - 1) = 5 - 3(-x + 2)<BR>\n" );
document.write( "let us expand everything, then collect terms...<BR>\n" );
document.write( "5x - 6x + 3 = 5 + 3x - 6<BR>\n" );
document.write( "-x + 3 = 3x - 1<BR>\n" );
document.write( "Now addx to both sides and then add 1 to both sides.<BR>\n" );
document.write( "3 = 4x - 1<BR>\n" );
document.write( "4 = 4x<BR>\n" );
document.write( "Now divide by 4 and we get<BR>\n" );
document.write( "x = 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );