document.write( "Question 37816: log (2-3x) - log x = log 2x \n" ); document.write( "
Algebra.Com's Answer #23336 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+log%282-3x%29+-+log%28x%29+=+log%282x%29+\"
\n" ); document.write( "\"+log%28%282-3x%29%2Fx%29+=+log%282x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and now raise both sides to power 10:
\n" ); document.write( "\"+%282-3x%29%2Fx+=+2x+\"
\n" ); document.write( "\"+2-3x+=+2x%5E2+\"
\n" ); document.write( "\"+2x%5E2+%2B+3x+-+2+=+0+\"
\n" ); document.write( "(2x - 1)(x + 2) = 0
\n" ); document.write( "so 2x-1 = 0 or x+2 = 0
\n" ); document.write( "so x=1/2 or x=-2\r
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\n" ); document.write( "\n" ); document.write( "CHECK:
\n" ); document.write( "put x=1/2 into \"+log%282-3x%29+-+log%28x%29+=+log%282x%29+\" and all th elog terms are fine.\r
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\n" ); document.write( "\n" ); document.write( "put x=-2 into \"+log%282-3x%29+-+log%28x%29+=+log%282x%29+\" and we get \"+log%288%29+-+log%28-2%29+=+log%28-4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and the last 2 log terms are not defined for this. So the answer to the question is x=1/2.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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