document.write( "Question 325989: rellie invests $12,000.a part of it earns 10% annual interest and the rest earns 9% annual interest.after a year, he earned $1,130 from his investments.how much is invested at each rate?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #233348 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let him invest $ x at 10%
\n" ); document.write( "so 12000-x will be invested at 9%
\n" ); document.write( "interest earned on both =$1130
\n" ); document.write( "..
\n" ); document.write( "0.1x+0.09(12000-x)=1130
\n" ); document.write( "0.1x+1080-0.09x=1130
\n" ); document.write( "0.01x=1130-1080
\n" ); document.write( "0.01x=50
\n" ); document.write( "x=50/0.01
\n" ); document.write( "x= 5000
\n" ); document.write( "$5000 invested @10%
\n" ); document.write( "$7000 invested @9%
\n" ); document.write( "
\n" );