document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325975>Question 325975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> TWO ANGLES ARE Complementary the sum of measure of the first angle and half of the second is 69 find the measures of the angles<BR>\n" );
document.write( "what is the measure of the smaller angle? what is the measure of the other angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233341 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x<BR>\n" );
document.write( "the other angle will be 90-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+1/2 *(90-x)=69<BR>\n" );
document.write( "LCM =2<BR>\n" );
document.write( "2x+90-x /2 = 69<BR>\n" );
document.write( "Multiply by2 <BR>\n" );
document.write( "x+90=2*69<BR>\n" );
document.write( "x+90=138<BR>\n" );
document.write( "add -90<BR>\n" );
document.write( "x+90-90=138-90<BR>\n" );
document.write( "x=48 deg one angle<BR>\n" );
document.write( "the other angle will ne 90 -48=42 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );