document.write( "Question 325959: A certain plane flying with the wind travels 540 mi in 2 hr. Later, flying against the same wind, the plane
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document.write( "travels 690 mi in 3 hr. Find the speed of the plane in still air and the speed of the wind.\r
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document.write( "I must solve this problem using a system of equations.\r
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document.write( "I got these two equations which led to a solution, but it doesn't seem like it was done right. 2(x + y) = 540 & 3(x – y) = 690 \n" );
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Algebra.Com's Answer #233313 by mananth(16946)![]() ![]() You can put this solution on YOUR website! with the wind plane travels 540 mi in 2 hr. \n" ); document.write( "flying against , the plane travels 690 mi in 3 hr. \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "let speed of plane in still air be x mph \n" ); document.write( "& speed of wind be y mph \n" ); document.write( ".. \n" ); document.write( "With wind \n" ); document.write( "Time taken = 540 / x+y= 2 \n" ); document.write( "540 =2x+2y \n" ); document.write( "270=x+y........................1 \n" ); document.write( ".. \n" ); document.write( "Against wind \n" ); document.write( "Time taken = 690/ x-y = 3 \n" ); document.write( ".. \n" ); document.write( "690=3x-3y \n" ); document.write( "230=x-y........................2 \n" ); document.write( ".. \n" ); document.write( "Add equation 1 & 2 \n" ); document.write( "x+y+x-y=270+230 \n" ); document.write( "2x=500 \n" ); document.write( "x=250 mph speed of plane \n" ); document.write( ".. \n" ); document.write( "plug the value of x in equation 1 \n" ); document.write( "270=250+y \n" ); document.write( "y= 20 mph the speed of wind \n" ); document.write( " \n" ); document.write( " |