document.write( "Question 325935: how do i evaluate sin[cos^-1(6/7)] ? \n" ); document.write( "
Algebra.Com's Answer #233297 by Apathious(24)\"\" \"About 
You can put this solution on YOUR website!
sin([arccos((6)/(7))])\r
\n" ); document.write( "\n" ); document.write( "Take the inverse cosine of (6)/(7) to get 0.5411.
\n" ); document.write( "sin((0.5411))\r
\n" ); document.write( "\n" ); document.write( "Remove the parentheses around the expression 0.5411.
\n" ); document.write( "sin(0.5411)\r
\n" ); document.write( "\n" ); document.write( "Take the sine of 0.5411 to get 0.5151.
\n" ); document.write( "0.5151
\n" ); document.write( "
\n" );