document.write( "Question 325908: -x+y=5
\n" ); document.write( "x-5y=-9
\n" ); document.write( "Solving systems by elimination
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Algebra.Com's Answer #233290 by Apathious(24)\"\" \"About 
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x+y=5_x-5y=-9\r
\n" ); document.write( "\n" ); document.write( "Multiply the first equation by -1 to make the coefficients of x have opposite signs.
\n" ); document.write( "-(x+y)=-(5)_x-5y=-9\r
\n" ); document.write( "\n" ); document.write( "Multiply -1 by the 5 inside the parentheses.
\n" ); document.write( "-(x+y)=-5_x-5y=-9\r
\n" ); document.write( "\n" ); document.write( "Multiply -1 by each term inside the parentheses.
\n" ); document.write( "-x-y=-5_x-5y=-9\r
\n" ); document.write( "\n" ); document.write( "Add the two equations together to eliminate x from the system.
\n" ); document.write( " x-5y=-9_- x-y=-5_ -6y=-14\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by -6.
\n" ); document.write( "y=(7)/(3)\r
\n" ); document.write( "\n" ); document.write( "Substitute the value found for y into the original equation to solve for x.
\n" ); document.write( "-x-((7)/(3))=-5\r
\n" ); document.write( "\n" ); document.write( "Multiply -1 by each term inside the parentheses.
\n" ); document.write( "-x-(7)/(3)=-5\r
\n" ); document.write( "\n" ); document.write( "Move all terms not containing x to the right-hand side of the equation.
\n" ); document.write( "-x=-(8)/(3)\r
\n" ); document.write( "\n" ); document.write( "Multiply -x by -1 to get x.
\n" ); document.write( "x=-(8)/(3)*-1\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by -1.
\n" ); document.write( "x=(8)/(3)\r
\n" ); document.write( "\n" ); document.write( "This is the final solution to the independent system of equations.
\n" ); document.write( "y=(7)/(3)_x=(8)/(3)
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