document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325893>Question 325893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I Solve the following using elimination method? I get lost when I try. The whole method confesses me I don't know where to start. Math is my weakness \r<BR>\n" );
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document.write( "4x-2y=16<BR>\n" );
document.write( "5x+7y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233284 by </B><A HREF=/tutors/aboutme.mpl?userid=Apathious><B>Apathious(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Apathious><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Apathious><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x-2y=16_5x+7y=1\r<BR>\n" );
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document.write( "Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 14.<BR>\n" );
document.write( "7*(4x-2y=16)_2*(5x+7y=1)\r<BR>\n" );
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document.write( "Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 14.<BR>\n" );
document.write( "7*(4x-2y)=7(16)_2*(5x+7y)=2(1)\r<BR>\n" );
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document.write( "Multiply 7 by each term inside the parentheses.<BR>\n" );
document.write( "7*(4x-2y)=112_2*(5x+7y)=2(1)\r<BR>\n" );
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document.write( "Multiply 7 by each term inside the parentheses.<BR>\n" );
document.write( "(28x-14y)=112_2*(5x+7y)=2(1)\r<BR>\n" );
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document.write( "Remove the parentheses around the expression 28x-14y.<BR>\n" );
document.write( "28x-14y=112_2*(5x+7y)=2(1)\r<BR>\n" );
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document.write( "Multiply 2 by each term inside the parentheses.<BR>\n" );
document.write( "28x-14y=112_2*(5x+7y)=2\r<BR>\n" );
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document.write( "Multiply 2 by each term inside the parentheses.<BR>\n" );
document.write( "28x-14y=112_(10x+14y)=2\r<BR>\n" );
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document.write( "Remove the parentheses around the expression 10x+14y.<BR>\n" );
document.write( "28x-14y=112_10x+14y=2\r<BR>\n" );
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document.write( "Add the two equations together to eliminate y from the system.<BR>\n" );
document.write( "10x+14y=2_<U>28x-14y=112<u>_38x    =114\r<BR>\n" );
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document.write( "Divide each term in the equation by 38.<BR>\n" );
document.write( "x=3\r<BR>\n" );
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document.write( "Substitute the value found for x into the original equation to solve for y.<BR>\n" );
document.write( "28(3)-14y=112\r<BR>\n" );
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document.write( "Multiply 28 by each term inside the parentheses.<BR>\n" );
document.write( "84-14y=112\r<BR>\n" );
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document.write( "Move all terms not containing y to the right-hand side of the equation.<BR>\n" );
document.write( "-14y=28\r<BR>\n" );
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document.write( "Divide each term in the equation by -14.<BR>\n" );
document.write( "y=-2\r<BR>\n" );
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document.write( "This is the final solution to the independent system of equations.<BR>\n" );
document.write( "x=3_y=-2 </SPAN>\n" );
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