document.write( "Question 325859: Solve by factoring and using the principle of zero products. Show all work necessary.\r
\n" ); document.write( "\n" ); document.write( "4x^2 - 12x = 16
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #233272 by Apathious(24)\"\" \"About 
You can put this solution on YOUR website!
4x^(2)-12x=16\r
\n" ); document.write( "\n" ); document.write( "To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side.
\n" ); document.write( "4x^(2)-12x-16=0\r
\n" ); document.write( "\n" ); document.write( "Factor out the GCF of 4 from each term in the polynomial.
\n" ); document.write( "4(x^(2))+4(-3x)+4(-4)=0\r
\n" ); document.write( "\n" ); document.write( "Factor out the GCF of 4 from 4x^(2)-12x-16.
\n" ); document.write( "4(x^(2)-3x-4)=0\r
\n" ); document.write( "\n" ); document.write( "For a polynomial of the form x^(2)+bx+c, find two factors of c (-4) that add up to b (-3). In this problem 1*-4=-4 and 1-4=-3, so insert 1 as the right hand term of one factor and -4 as the right-hand term of the other factor.
\n" ); document.write( "4(x+1)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 4. Dividing 0 by any non-zero number is 0.
\n" ); document.write( "(x+1)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "Set each of the factors of the left-hand side of the equation equal to 0.
\n" ); document.write( "x+1=0_x-4=0\r
\n" ); document.write( "\n" ); document.write( "Since 1 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 1 from both sides.
\n" ); document.write( "x=-1_x-4=0\r
\n" ); document.write( "\n" ); document.write( "Set each of the factors of the left-hand side of the equation equal to 0.
\n" ); document.write( "x=-1_x-4=0\r
\n" ); document.write( "\n" ); document.write( "Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.
\n" ); document.write( "x=-1_x=4\r
\n" ); document.write( "\n" ); document.write( "The complete solution is the set of the individual solutions.
\n" ); document.write( "x=-1,4
\n" ); document.write( "
\n" );