document.write( "Question 37809: Use the compound interest equation A= P(1 + r/n)^nt to find how long, to the nearest tenth of a year, it will take a $5000 investment to double if it is invested at 7% interest compounded quarterly. \n" ); document.write( "
Algebra.Com's Answer #23324 by Alwayscheerful(414)\"\" \"About 
You can put this solution on YOUR website!
In your compound interest formula,
\n" ); document.write( "P is the principle (5000)
\n" ); document.write( "r is the rate (.07)
\n" ); document.write( "n is the number of times it compounds (4)
\n" ); document.write( "t is the time (variable)\r
\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Br%2Fn%29%5Ent\"\r
\n" ); document.write( "\n" ); document.write( "Since you start out with $5000 and you want it to double, A will be $10,000.
\n" ); document.write( "Now all you need to do is plug the numbers into the formula. \r
\n" ); document.write( "\n" ); document.write( "\"10000=5000%281%2B%28.07%2F4%29%29%5E%284t%29\"
\n" ); document.write( "\"2=%281%2B.0175%29%5E%284t%29\"
\n" ); document.write( "\"2=1.0175%5E%284t%29\"\r
\n" ); document.write( "\n" ); document.write( "Now to solve for t, you need to use logs. \r
\n" ); document.write( "\n" ); document.write( "\"log%282%29=log%281.0175%29%5E%284t%29\"
\n" ); document.write( "\"log%282%29%2Flog%281.0175%29=4t\"
\n" ); document.write( "\"39.9539818154=4t\"
\n" ); document.write( "\"t=9.988495\"\r
\n" ); document.write( "\n" ); document.write( "Round to the nearest tenth\r
\n" ); document.write( "\n" ); document.write( "Answer: \"highlight%2810%29\"years\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!
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