document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325772>Question 325772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Several questions (2)\r<BR>\n" );
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document.write( "1)  An outoor ropes course includes a cable that is connected between 2 trees; trees are 24 ft. apart.  Cable slopes down from a height of 35 ft. on one tree to a height of 25 ft. on the other tree. How long is the cable?\r<BR>\n" );
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document.write( "- I do not even know how to approach; attempted to visualize and set up equation as area of triangle where base is 24 ft and height is 35 ft.????<BR>\n" );
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document.write( "2) Find the total area of rectangles: 1st rectangle     L=3; W=3;<BR>\n" );
document.write( "                                      2nd rectangle     L = 4x; W=4x\r<BR>\n" );
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document.write( "my answer: since A = LW;  (4x + 3)^ where ^ is 2;  so based on that reasoning, answer is 4x^ +24x + 9  (re: ^ is 2).\r<BR>\n" );
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document.write( "I appreciate any and all assistance; thank you.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233217 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> # 1\r<BR>\n" );
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document.write( "Hint: If you draw the picture, you get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/tree_drawing.png\">\r<BR>\n" );
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document.write( "From there, use the pythagorean theorem <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > to solve for 'x' (use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=10 ALIGN=MIDDLE  ALT=\"a=10\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=24 ALIGN=MIDDLE  ALT=\"b=24\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=x ALIGN=MIDDLE  ALT=\"c=x\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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document.write( "# 2\r<BR>\n" );
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document.write( "Area of first rectangle: 3*3=9\r<BR>\n" );
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document.write( "Area of second rectangle: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2A4x=16x%5E2 ALIGN=MIDDLE  ALT=\"4x%2A4x=16x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Total area: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16x%5E2%2B9 ALIGN=MIDDLE  ALT=\"16x%5E2%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" > (just add the two individual areas) </SPAN>\n" );
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