document.write( "Question 4842: solve by using the addition method\r
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document.write( "x-y=100
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document.write( "0.20x+0.06y=150 \n" );
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Algebra.Com's Answer #2332 by Abbey(339) ![]() You can put this solution on YOUR website! I think you mean solve by using the elimination method...\r \n" ); document.write( "\n" ); document.write( " x -y = 100 \n" ); document.write( ".2x +.6y = 150\r \n" ); document.write( "\n" ); document.write( "Multiply the second equation by -5\r \n" ); document.write( "\n" ); document.write( " x- y = 100 \n" ); document.write( "-x+-3y =-750\r \n" ); document.write( "\n" ); document.write( "Add the two equations to get\r \n" ); document.write( "\n" ); document.write( "-4y=-650\r \n" ); document.write( "\n" ); document.write( "Divide both sides by -4 \n" ); document.write( "y=162.5\r \n" ); document.write( "\n" ); document.write( "Substitute 325 into first equation to get \n" ); document.write( "x-162.5=100 \n" ); document.write( "Add 162.5 to both sides \n" ); document.write( "x=262.5\r \n" ); document.write( "\n" ); document.write( "check your answer with the second equation: \n" ); document.write( ".2(262.5)+.6(162.5)=150 \n" ); document.write( "52.5+97.5=150 (True statement)\r \n" ); document.write( "\n" ); document.write( "The solution is (262.5,162.5) \n" ); document.write( " \n" ); document.write( " |